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f(x)=b*x^a
#2
b = 1/4
a = 4

That sounds right to me.
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Messages In This Thread
f(x)=b*x^a - by Guru - 11-20-2011, 03:52 AM
RE: f(x)=b*x^a - by Daniel Faraday - 11-20-2011, 11:16 PM

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